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What is the period of a 1.0 m simple pendulum where g = 9.8 m/s^2?
A2.0 s
B1.0 s
C3.1 s
D6.3 s
Answer & Solution
Correct answer: A. 2.0 s
T = 2 pi root(1/9.8) = 2 pi x 0.319 = about 2.0 s.
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