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A 0.25 kg mass hangs on a spring of constant 100 N/m. What is its period?
A0.31 s
B0.63 s
C1.57 s
D3.14 s
Answer & Solution
Correct answer: A. 0.31 s
T = 2 pi root(0.25/100) = 2 pi x 0.05 = 0.314 s.
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