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How much heat melts 2 kg of ice at 0 °C if Lf is 3.33 × 10^5 J/kg?
A1.33 × 10^6 J
B1.67 × 10^5 J
C6.66 × 10^5 J
D3.33 × 10^5 J
Answer & Solution
Correct answer: C. 6.66 × 10^5 J
Q = m Lf = 2 × 3.33 × 10^5 = 6.66 × 10^5 J.
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