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A ball is launched at 20 m/s at 30 degrees. Taking g = 10 m/s^2, what is the greatest height reached?
A10 m
B5 m
C20 m
D2.5 m
Answer & Solution
Correct answer: B. 5 m
Vertical speed is 20 x 0.5 = 10 m/s, so height = 10^2/(2 x 10) = 5 m.
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