$\displaystyle\int \sec^2 x\,dx$ equals:
A$-\cot x + C$
B$\tan x + C$
C$\sec x\tan x + C$
D$\sec x + C$
Answer & Solution
Correct answer: B. $\tan x + C$
Since d/dx(tan x) = sec²x, ∫sec²x dx = tan x + C.
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