$\displaystyle\int \sin x\,dx$ equals:
A$-\cos x + C$
B$\sin x + C$
C$\cos x + C$
D$-\sin x + C$
Answer & Solution
Correct answer: A. $-\cos x + C$
Since d/dx(−cos x) = sin x, ∫sin x dx = −cos x + C.
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