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For $f(x) = x^2 - 4x + 3$, the critical point occurs at:

A$x = 3$
B$x = 4$
C$x = 2$
D$x = 0$
Answer & Solution
Correct answer: C. $x = 2$
We have f'(x) = 2x − 4. That is f'(x) = 0 ⟹ x. So f'(x) = 2.
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