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The point on the x-axis equidistant from (7, 6) and (3, 4) is
A(15/2, 0)
B(13/2, 0)
C(10, 0)
D(5, 0)
Answer & Solution
Correct answer: A. (15/2, 0)
Equating squared distances: x² – 14x + 85 = x² – 6x + 25 gives x = 15/2.
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