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In triangle PQR with P(2, 1), Q(–2, 3), R(4, 5), the median through R is
A4x – 3y + 8 = 0
B3x – 4y – 8 = 0
C3x – 4y + 8 = 0
D3x + 4y – 8 = 0
Answer & Solution
Correct answer: C. 3x – 4y + 8 = 0
The mid-point of PQ is (0, 2); the line through it and R(4, 5) has slope 3/4, giving 3x – 4y + 8 = 0.
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