Home › CBSE Class 11 (Commerce) › Mathematics › Straight Lines › The line through (–2, 6) and (4, 8) is perpendic…
The line through (–2, 6) and (4, 8) is perpendicular to the line through (8, 12) and (x, 24). Find x.
A12
B8
C4
D–4
Answer & Solution
Correct answer: C. 4
The first slope is 1/3, so the second must be –3: 12/(x – 8) = –3 gives x = 4.
Related questions
The lines 3x + 2y − 5 = 0 and kx + 4y + 1 = 0 are parallel. Find k.The points (1, 2), (3, 6) and (k, 10) are collinear. Find k.A line is perpendicular to 2x − 3y + 4 = 0. What is its slope?Find the distance between the parallel lines y = 2x + 3 and y = 2x − 2.What is the perpendicular distance of the point (2, 1) from the line 3x − 4y + 5 = 0?In the general linear equation Ax + By + C = 0, what must hold for A and B?The line 3x + 4y = 12 and the two coordinate axes enclose a triangle of areaWhich line cuts off intercepts 4 on the x-axis and 5 on the y-axis?