Home › CBSE Class 11 (Commerce) › Mathematics › Introduction to Three-dimensional Geometry › Three vertices of a parallelogram ABCD are A(3,-…
Three vertices of a parallelogram ABCD are A(3,-1,2), B(1,2,-4), C(-1,1,2). Vertex D is
A(1, 2, 8)
B(-1, 4, -4)
C(1, -2, 8)
D(5, 0, -4)
Answer & Solution
Correct answer: C. (1, -2, 8)
Diagonals bisect each other, so D = A + C - B = (3 - 1 - 1, -1 + 1 - 2, 2 + 2 + 4) = (1, -2, 8).
Related questions
Geometry was first extended beyond three dimensions around which time?Who introduced the three coordinate planes now in use, in a 1715 letter to Leibnitz?Which mathematician took up three dimensional coordinate geometry systematically in 1748?Who first gave a systematic development of analytical solid geometry in 1700?Who is called the father of analytical geometry?Two points differ only in z: (1, 2, 3) and (1, 2, 7). Their distance isThe plane determined by the x-axis and y-axis together is called theGiven P(2, 4, 5), the foot F of P on the ZX-plane has coordinates