Practice free →
Home › CBSE Class 11 (Commerce) › Mathematics › Introduction to Three-dimensional Geometry › The distance from (1, 2, 3) to (3, 6, 9) is

The distance from (1, 2, 3) to (3, 6, 9) is

A4 root 14
Broot 14
C3 root 14
D2 root 14
Answer & Solution
Correct answer: D. 2 root 14
The differences 2, 4, 6 give root(4 + 16 + 36) = root 56 = 2 root 14.
Solve this in the app — CBSE Class 11 (Commerce) practice & 24k+ MCQs →
Related questions