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NaCl has lattice enthalpy +788 and hydration enthalpy -784 kJ/mol. What is ΔsolH?

A+1572 kJ/mol
B-4 kJ/mol
C-1572 kJ/mol
D+4 kJ/mol
Answer & Solution
Correct answer: D. +4 kJ/mol
ΔsolH = 788 + (-784) = +4 kJ/mol, so dissolving NaCl is slightly endothermic.
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