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If $f(x) = 2x$ and $g(x) = x + 1$, then $(g\circ f)(x)$ equals:

A$2(x+1)$
B$2x + 2$
C$2x + 1$
D$x + 1$
Answer & Solution
Correct answer: C. $2x + 1$
We have (g∘f)(x) = g(f(x)). That is (g∘f)(x) = g(2x). So (g∘f)(x) = 2x + 1.
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