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For the homogeneous gas-phase reaction $A_{(g)} + B_{(g)} \rightleftharpoons C_{(g)} + D_{(g)}$ at equilibrium, the expression for the equilibrium constant $K_c$ is:
A$\dfrac{[C][D]}{[A][B]}$
B$\dfrac{[C]-[D]}{[A]-[B]}$
C$\dfrac{[A][B]}{[C][D]}$
D$\dfrac{[A]+[B]}{[C]+[D]}$
Answer & Solution
Correct answer: A. $\dfrac{[C][D]}{[A][B]}$
Equilibrium constant in terms of molar concentrations is written products over reactants, with each species raised to its stoichiometric coefficient. Here all coefficients are 1, so $K_c = \dfrac{[C][D]}{[A][B]}$.
This convention is the load-bearing rule: products on top, reactants on the bottom, exponents from the balanced equation. Reversing the order is the most common student error and gives the reciprocal.
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