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A 5 H coil has its current changing at 2 A/s. What is the magnitude of the self-induced emf?

A2.5 V
B10 V
C3 V
D7 V
Answer & Solution
Correct answer: B. 10 V
Back emf magnitude equals L times dI/dt, which is 5 x 2 = 10 V.
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