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An electron moves at 2 × 10^6 m/s perpendicular to a 0.5 T field. Force on it?
A1.6 × 10^-19 N
B3.2 × 10^-13 N
C1.6 × 10^-13 N
D8.0 × 10^-14 N
Answer & Solution
Correct answer: C. 1.6 × 10^-13 N
F = e v B = 1.6 × 10^-19 × 2 × 10^6 × 0.5 = 1.6 × 10^-13 N.
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