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A 0.5 m wire carrying 4 A is at 30° to a 0.2 T field. Force on it?
A0.35 N
B0.1 N
C0.2 N
D0.4 N
Answer & Solution
Correct answer: C. 0.2 N
F = I l B sin 30° = 4 × 0.5 × 0.2 × 0.5 = 0.2 N.
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