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What is the experimental value of the permittivity of free space ε0?
A9 × 109 C2 N–1 m–2
B1.6 × 10–19 C2 N–1 m–2
C8.854 × 10–12 C2 N–1 m–2
D6.67 × 10–11 C2 N–1 m–2
Answer & Solution
Correct answer: C. 8.854 × 10–12 C2 N–1 m–2
Measurements give ε0 as 8.854 × 10–12 C2 N–1 m–2, which fixes the size of k.
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