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A steady current of 1.6 A flows in a wire. About how many electrons cross a section each second?
A1.6 x 10^19
B1 x 10^20
C1 x 10^19
D1.6 x 10^-19
Answer & Solution
Correct answer: C. 1 x 10^19
N = I/e = 1.6 / (1.6 x 10^-19) = 1 x 10^19 electrons per second.
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