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Charges of 2 μC and 3 μC sit 0.6 m apart in vacuum. Their potential energy is
A0.09 J
B0.9 J
C0.18 J
D0.03 J
Answer & Solution
Correct answer: A. 0.09 J
U = (9×10⁹)(2×10⁻⁶)(3×10⁻⁶)/0.6 = 0.054/0.6 = 0.09 J.
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