alleryFor any hyperbola, the eccentricity $e$ satisfies:
A$e = 0$
B$e < 1$
C$e = 1$
D$e > 1$
Answer & Solution
Correct answer: D. $e > 1$
Eccentricity scale across the conic family:
| Conic | $e$ |
|---|---|
| Circle | $0$ |
| Ellipse | $0 < e < 1$ |
| Parabola | $e = 1$ |
| **Hyperbola** | **$e > 1$** |
For a hyperbola, $c^2 = a^2 + b^2 \Rightarrow c > a \Rightarrow e = c/a > 1$.
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