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Taking R0 = 1.2 fm, what is the radius of a nucleus with A = 27?
A3.6 fm
B2.4 fm
C4.8 fm
D1.2 fm
Answer & Solution
Correct answer: A. 3.6 fm
The cube root of 27 is 3, so R = 1.2 × 3 = 3.6 fm.
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