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A series LCR circuit has R = 100 ohm and a 10 V peak source. Peak current at resonance?
A0.01 A
B10 A
C0.1 A
D1.0 A
Answer & Solution
Correct answer: C. 0.1 A
At resonance the whole source voltage appears across R, so im = vm/R = 10/100 = 0.1 A.
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