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3 sin⁻¹x = sin⁻¹(3x - 4x³) holds for x in
A[-1, 1]
B[-1/2, 1/2]
C[1/2, 1]
D[0, 1]
Answer & Solution
Correct answer: B. [-1/2, 1/2]
With x = sin θ, sin 3θ = 3x - 4x³, and 3θ stays inside [-π/2, π/2] only when |x| ≤ 1/2.
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