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Why must the domain of sine be restricted before its inverse is defined?
ASine is not continuous
BSine is not one-one over all of R
CSine takes only positive values
DSine has no maximum value
Answer & Solution
Correct answer: B. Sine is not one-one over all of R
Sine repeats its values, so it is not one-one on R; restricting to [-π/2, π/2] makes it bijective onto [-1, 1].
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