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For principal cosec⁻¹, [-π/2, π/2] must lose which point?
Aπ/2
B-π/2
Cπ/4
D0
Answer & Solution
Correct answer: D. 0
Cosecant is undefined at 0 because sin 0 = 0, so 0 is removed from [-π/2, π/2].
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