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Compute tan⁻¹(√3) minus sec⁻¹(-2) using principal values.
Aπ
Bπ/3
C-π/3
D2π/3
Answer & Solution
Correct answer: C. -π/3
tan⁻¹(√3) = π/3 and sec⁻¹(-2) = 2π/3, so the difference is π/3 - 2π/3 = -π/3.
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