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Home › CBSE Class 12 (Commerce) › Mathematics › Inverse Trigonometric Functions › Determine sec⁻¹(2/√3) using the principal value …

Determine sec⁻¹(2/√3) using the principal value branch.

Aπ/3
Bπ/4
Cπ/2
Dπ/6
Answer & Solution
Correct answer: D. π/6
sec(π/6) = 1/cos(π/6) = 2/√3, and π/6 lies in [0, π] excluding π/2.
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