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f: N to N, f(n) = (n+1)/2 for odd n and n/2 for even n. Which equality breaks one-one?
Af(4) = f(5)
Bf(1) = f(2)
Cf(2) = f(3)
Df(1) = f(3)
Answer & Solution
Correct answer: B. f(1) = f(2)
f(1) = (1+1)/2 = 1 and f(2) = 2/2 = 1, so two inputs share an output and f is not bijective.
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