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Minimise 3x + 2y with x + y ≥ 8, 3x + 5y ≤ 15, x, y ≥ 0. What happens?
AMinimum is 16 at (8,0)
BMinimum is 6 at (0,3)
CNo feasible solution
DMany optimal points
Answer & Solution
Correct answer: C. No feasible solution
Points with x + y ≥ 8 force 3x + 5y to be at least 24, which exceeds 15, so the feasible region is empty.
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