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The parallel lines r = i + 2j - 4k + λ(2i + 3j + 6k) and r = 3i + 3j - 5k + μ(2i + 3j + 6k) are how far apart?
A293/7
B√293/9
C√293/7
D√293/49
Answer & Solution
Correct answer: C. √293/7
With a2 - a1 = 2i + j - k, the cross product with b is -9i + 14j - 4k, of length √293, divided by |b| = 7.
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