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The line through (5, 2, -4) parallel to 3i + 2j - 8k has Cartesian form:
A(x-5)/3 = (y-2)/2 = (z+4)/-8
B(x-3)/5 = (y-2)/2 = (z+8)/-4
C(x-5)/3 = (y-2)/2 = (z-4)/-8
D(x+5)/3 = (y+2)/2 = (z-4)/-8
Answer & Solution
Correct answer: A. (x-5)/3 = (y-2)/2 = (z+4)/-8
Subtracting the point coordinates gives x - 5, y - 2 and z + 4 over the direction ratios 3, 2, -8.
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