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For A = [[2, 4], [6, 8]], the matrix (1/2)A is:
A[[2, 1], [4, 3]]
B[[1, 2], [3, 4]]
C[[4, 8], [12, 16]]
D[[1, 4], [3, 8]]
Answer & Solution
Correct answer: B. [[1, 2], [3, 4]]
Each entry is halved: 2, 4, 6, 8 become 1, 2, 3, 4.
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