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Integrate e^x (1/x - 1/x^2) over x > 0.
Ae^x / x
Be^x log x
Ce^x / x^2
D-e^x / x
Answer & Solution
Correct answer: A. e^x / x
With f = 1/x, f' = -1/x^2, so the integral is e^x f(x) = e^x / x.
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