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Find the integral of x^2 e^x by repeating parts twice.
Ae^x (x^2 + 2x + 2)
Be^x (x^2 - 2x + 2)
Ce^x (x^2 - x + 1)
De^x (x^2 - 2x - 2)
Answer & Solution
Correct answer: B. e^x (x^2 - 2x + 2)
Two rounds of parts give x^2 e^x - 2x e^x + 2e^x = e^x (x^2 - 2x + 2).
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