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Integrate tan^-1 x using 1 as the second function:
Ax tan^-1 x - 2 log (1+x^2)
Bx tan^-1 x + (1/2) log (1+x^2)
Cx tan^-1 x - (1/2) log (1+x^2)
Dx tan^-1 x + 2 log (1+x^2)
Answer & Solution
Correct answer: C. x tan^-1 x - (1/2) log (1+x^2)
By parts this gives x tan^-1 x minus the integral of x/(1 + x^2), which is (1/2) log (1 + x^2).
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