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Completing the square, integrate 1/(x^2 + 2x + 5):
A(1/2) log (x^2+2x+5)
B(1/2) tan^-1 (x/2)
C(1/2) tan^-1 ((x+1)/2)
Dtan^-1 ((x + 1)/2)
Answer & Solution
Correct answer: C. (1/2) tan^-1 ((x+1)/2)
Completing the square gives (x + 1)^2 + 4, so the integral is (1/2) tan^-1 ((x + 1)/2).
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