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Given the form 1/(x^2 + a^2), integrate 1/(x^2 + 9).
A(1/9) tan^-1 x
B(1/3) log (x^2 + 9)
C(1/3) tan^-1 (x/3)
D3 tan^-1 (x/3)
Answer & Solution
Correct answer: C. (1/3) tan^-1 (x/3)
Using the form 1/(x^2 + a^2) with a = 3 gives (1/a) tan^-1 (x/a).
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