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Expand (x + 1/x)^2 and integrate to get:
Ax^3/3 + 2x + 1/x
Bx^3/3 + 1/x
Cx^3/3 + 2x - 1/x
D(x + 1/x)^3 / 3
Answer & Solution
Correct answer: C. x^3/3 + 2x - 1/x
Expanding gives x^2 + 2 + x^(-2), whose integral is x^3/3 + 2x - 1/x.
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