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Substituting t = 1 + cos x, the integral of sin x/(1 + cos x) is:
Alog (1 + cos x)
Blog (1 + sin x)
C-log (1 - cos x)
D-log (1 + cos x)
Answer & Solution
Correct answer: D. -log (1 + cos x)
Put t = 1 + cos x, so dt = -sin x dx, giving -log |t|.
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