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Which is the antiderivative of (2x + 1)^3?
A(2x + 1)^4 / 4
B3(2x + 1)^2
C(2x + 1)^4 / 8
D(2x + 1)^4
Answer & Solution
Correct answer: C. (2x + 1)^4 / 8
With t = 2x + 1, dx = dt/2, so the integral is t^4/(4 x 2) = (2x + 1)^4 / 8.
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