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Put t = 1 + x^3 and find the integral of x^2 / (1 + x^3).
Alog |1 + x^3|
B3 log |1 + x^3|
C(1/3) tan^-1 x^3
D(1/3) log |1 + x^3|
Answer & Solution
Correct answer: D. (1/3) log |1 + x^3|
With t = 1 + x^3, x^2 dx = dt/3, so the integral becomes (1/3) log |t|.
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