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Since 2x is the derivative of 1 + x^2, the integral of 2x/(1 + x^2) is:
A2 log (1 + x)
Btan^-1 (1+x)
Clog (1 + x^2)
D1 / (1 + x^2)
Answer & Solution
Correct answer: C. log (1 + x^2)
The numerator is the derivative of the denominator, so the integral is log (1 + x^2).
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