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Find y when dy/dx = y and y = 3 at x = 0.
Ay = 3 + e^x
By = e^(3x)
Cy = 3e^x
Dy = e^x + 2
Answer & Solution
Correct answer: C. y = 3e^x
The general solution is y = Ce^x, and y(0) = 3 gives C = 3.
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