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Find the curve through (0, 2) satisfying dy/dx = x/y.

Ay^2 = 2x^2 + 4
By^2 = x^2 + 2
Cy = x + 2
Dy^2 = x^2 + 4
Answer & Solution
Correct answer: D. y^2 = x^2 + 4
y dy = x dx gives y^2 = x^2 + C, and (0, 2) gives C = 4.
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