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Find the curve through (1, 1) given x dy = (2x^2 + 1) dx, with x > 0.
Ay = x^2 + 2 ln x
By = x^2 + 1/x
Cy = 2x^2 + ln x
Dy = x^2 + ln x
Answer & Solution
Correct answer: D. y = x^2 + ln x
dy = (2x + 1/x) dx gives y = x^2 + ln x + C, and (1, 1) gives C = 0.
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