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Which differential equation has y = e^(-3x) as a solution?
Ady/dx - 3y = 0
Bdy/dx + 3y = 0
Cdy/dx + y = 3
D3 dy/dx + y = 0
Answer & Solution
Correct answer: B. dy/dx + 3y = 0
Differentiating gives dy/dx = -3e^(-3x) = -3y, so dy/dx + 3y = 0.
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