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Find the order and degree of [1 + (y')^2]^(3/2) = y''.
AOrder 1, degree 2
BOrder 2, degree 3
COrder 2, degree 1
DOrder 2, degree 2
Answer & Solution
Correct answer: D. Order 2, degree 2
Squaring removes the fractional power: (1 + y'^2)^3 = (y'')^2, so order is 2 and degree is 2.
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