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At which point does y = x² − 4x + 5 have a horizontal tangent?
A(0, 5)
B(2, 1)
C(2, 5)
D(4, 5)
Answer & Solution
Correct answer: B. (2, 1)
dy/dx = 2x − 4 is zero at x = 2, and y = 4 − 8 + 5 = 1.
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